# Vector Details with Diagram (Part 3)

## Vector Details with Diagram (Part 3)

### Vector Details with Diagram (Part 3)

If **Then=? **

**Vector Details with Diagram (Part 3)**

**Dot product or Scalar product:**

**Definition:**The scalar or dot product of two vectors is a scalar equal to the product of the magnitude of the vectors and the cosine of the angle between them.

**Explanation:** Let OA and OB represent two vectors andrespectively both in magnitude and direction [Fig: Right side]. Both these vectors are inclined to each other by an angle q. Now, according to the definition of scalar product, we get,

From the figure, BM is normal on OA and AN is normal on OB

∴ OM = OB cosθ or, OM = Q cosθ ∴

= (OM) = (magnitude of) (projection of on) Thus, = (magnitude of) (projection of on) This means that **the scalar product of two vectors is the product of the magnitude of either vector and the projection of the in its direction.**

**Important condition about scalar product: ** (i) If θ = 0°, then. This is the condition for two vectors to be parallel to each other. (ii) If θ = 90°, then. This is the condition for two vectors to be perpendicular to each other. (iii) If θ = 180°, then. This is the condition for two vectors to be parallel but opposite directed.

**Dot product of rectangular unit vector:** Thethree rectangular unit vectors are andare perpendicular to each other

(a)

(b)

**Vector Details** with Diagram

*Vector Details with Diagram (Part 3)*

**Vector product or cross product:**

**Definition: **The vector or cross product of any two vectors is another vector, the magnitude of which is obtained by multiplying the magnitudes of the constituent vectors with the sine of the angle between them and direction is perpendicular to the plane containing the vectors.

**Explanation: **Let and be the two vectors acting at O making an angle θ. According to definition the vector product is, Here is a unite vector which represent the direction of and. The direction of is

found from

the right-handed screw rule. is a unit vector which denoted the direction of the resultant of

If then the direction of R is perpendicular to the plane of and

(Magnitude of P) (Magnitude of Q along the perpendicular direction of P) Again,

(Magnitude of Q) (Magnitude of P along the perpendicular direction of Q)

I.e. Cross product does dos obey commutative law.

**Important condition about vector product: **

(i) When θ = 0°, then. This is the condition that two vectors are parallel to each other.

(ii) When θ = 90°, then. This is the condition that two vectors are perpendicular to each other.

(iii) When θ = 180°, then. This is the condition that two vectors are parallel and opposite to each other.

**Cross product or vector product of rectangular unit vector:**

Thethree rectangular unit vectors are andare perpendicular to each other

(a)

(b)

**The scalar or dot product obeys commutative law but Cross product does dos obey commutative law:**

Let the angle between the vectors andis a, then Again, From (1) and (2) we get, i.e. the **scalar or dot product obeys **

### Vector Details with Diagram (Part 3)

**commutative law****. **

On the other hand the direction of andare opposite of each other, but the magnitude is the same, i.e. And From (3) and (4) we get, I.e. the** cross product does dos obey commutative law.**

**Commutative Law****:**

If are two vector of same nature then

This is Commutative Law.

**Proof:**Suppose ORQP is a parallelogram with diagonal OQ and ;

From ∆OPQ, And from ∆ORQ,

From (1) and (2) we get I.e.

**Associative Law: **

If are three vectors of same physical nature, then, this is the Associative law for vector addition. **Proof:** Suppose ,and.

Appling triangle rule we can write from ∆ OPQ, and from ∆ PQR, and from ∆ OQR, I.e. again from ∆ OQR, I.e. This is Associative law:

**Distributive law: **Distributive law of scalar product is ** **

**Proof:** Suppose are three vectors Now From the figure, we get, ** **

**The equation of a position vector in three dimensional reference system i.e. proof of ****:**

Suppose, OX, OY and OZ be three lines perpendicular to each other and represent X, Y and Z axis respectively. Is a position vector which is represented by line OP, i.e. . The co-ordinate of P is (x,y,z) and ,and are the unit vectors along the axis X, Y and Z respectively. PN is drawn normal to plane XY and PQ is normal to OZ. ON is joined. NL and NM is drawn normal to OX and OY respectively. From figure, OL = x, OM = y, NP = z; By the triangle Law,

Again From figure we get, *OP ^{2}=ON^{2}+NP^{2}*

* **OP ^{2 }= OL^{2}+LN^{2}+NP^{2}*

* **OP ^{2 }= OL^{2}+OM^{2}+OQ^{2} *

**Vector Resolution:** A vector quantity can be resolved into two or more vectors in different directions. Each resolving vector is known as component of the original vector. The process of resolving a vector into two or more vector is called vector resolution or resolution of vector. Let be a vector acting at a point O, along OC. The vector is to be resolved into two components. Let and be the two resolved components acting along OA and OB respectively making at angle α and β with the resultant vector. Let us complete the parallelogram OACB. Now from the law of triangle of addition, we get, i.e. To express the com

ponent vector in scalar form, we get,

From the sine law of triangle, and

Now, if the vectorresolved in to perpendicularly, then α + β = 90°

∴ sin (α + β) = sin 90° = 1 and α + β = 90° ∴ β = 90°- α

and

∴ sin β = sin (90 – α) = cos α therefore, P = R sin β

∴P = R cos α and Q = R sin α

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Vector Details with Diagram (Part 3)

Vector Details with Diagram (Part 2)

Vector Details with Diagram (Part 1)

Vector Details with Diagram (Part 3)

Vector Details with Diagram (Part 3)

Vector Details with Diagram (Part 3)